Geometry Exercises for the ACT Math Exam
Geometry exercises and problems on the ACT math test usually include various geometrical concepts on both coordinate geometry and plane geometry.
- Exercises on Angle Measurement
- Exercises on Hypotenuse Length
- Exercises on Diameter
- Exercises on Calculating Area
- Exercises on Calculating Circumference
- Exercises on Volume
- Exercises on Finding Midpoints
- Exercises on Computing Slope
ACT Geometry Download
It covers all of the geometry problems that you will see on the actual exam.
Geometry Questions on the ACT Test
You will need to know coordinate geometry for two-dimensional graphic representations of geometry problems like:
- Calculating the slope of the line
- Determining the midpoint between two points
- Using the distance formula to find the distance between two points on a line
Coordinate geometry is included in the algebra section of the math test.
That is because you need to understand how to use certain algebraic principles in order to solve coordinate geometry problems.
You will also need to know plane geometry for other geometry problems.
Plane geometry includes calculations relating to geometric figures such as:
Formulas for Geometry Exercises
Here are some of the formulas you will need in order to work out practice math problems for geometry.
The midpoints of two points on a two-dimensional graph are calculated by using this formula:
(x1 + x2) ÷ 2 , (y1 + y2) ÷ 2
Example: Find the coordinates (x, y) of the midpoint of the line segment on a graph that connects the points (−4, 8) and (2, −6).
x and y intercepts:
Questions about x and y intercepts are asking you to find the point at which a line crosses the x or y axes of a two-dimensional graph. For instance:
What are the x and y intercepts of: 9x2 + 4y2 = 36
Here is the slope formula: y = mx + b
Remember that m is the slope, b is the y intercept (the point at which the line crosses the y axis), and x and y are points on the graph.
Area of a circle:
π × R2 (radius squared)
Area of a square or rectangle:
length × width
Circumference of a circle:
π × diameter (diameter = radius × 2)